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What happens when you breed an engineer with an accountant?
Poor kids
Quote from: Emo EMAW on April 19, 2016, 02:26:46 PMWhat's the biggest percentage swing you've managed to achieve with a counter offer? Thanks for the help folks. Top notch.
What's the biggest percentage swing you've managed to achieve with a counter offer?
Wacky, what I'm asking is, when you're interviewing with another firm and they offer x, and you counter offer y, and you ultimately agree on z, what is the percentage represented by (z-x)/x. Got it?
wacky is trying to break his single day brags record today.
Quote from: Emo EMAW on April 20, 2016, 02:28:44 PMWacky, what I'm asking is, when you're interviewing with another firm and they offer x, and you counter offer y, and you ultimately agree on z, what is the percentage represented by (z-x)/x. Got it?It's got to be a function of y, although I would say z asymptotically approaches zero if y increases too much above x.
Quote from: Mrs. Gooch on April 20, 2016, 02:31:13 PMQuote from: Emo EMAW on April 20, 2016, 02:28:44 PMWacky, what I'm asking is, when you're interviewing with another firm and they offer x, and you counter offer y, and you ultimately agree on z, what is the percentage represented by (z-x)/x. Got it?It's got to be a function of y, although I would say z asymptotically approaches zero if y increases too much above x.How in the world would z approach zero? Who counter offers with 0? I think you mean z approaches x? That doesn't make any sense either. It's like you're suggesting some sort of laffer curve relationship.
Quote from: Emo EMAW on April 20, 2016, 02:35:41 PMQuote from: Mrs. Gooch on April 20, 2016, 02:31:13 PMQuote from: Emo EMAW on April 20, 2016, 02:28:44 PMWacky, what I'm asking is, when you're interviewing with another firm and they offer x, and you counter offer y, and you ultimately agree on z, what is the percentage represented by (z-x)/x. Got it?It's got to be a function of y, although I would say z asymptotically approaches zero if y increases too much above x.How in the world would z approach zero? Who counter offers with 0? I think you mean z approaches x? That doesn't make any sense either. It's like you're suggesting some sort of laffer curve relationship.No, I'm saying if your counter is too high they are going pull the offer altogether.
Job to job.
Quote from: Emo EMAW on April 20, 2016, 02:24:58 PMJob to job.that's not a counter offer. A counter offer is when you get a raise offered with the current employer
Quote from: Mrs. Gooch on April 20, 2016, 02:36:40 PMQuote from: Emo EMAW on April 20, 2016, 02:35:41 PMQuote from: Mrs. Gooch on April 20, 2016, 02:31:13 PMQuote from: Emo EMAW on April 20, 2016, 02:28:44 PMWacky, what I'm asking is, when you're interviewing with another firm and they offer x, and you counter offer y, and you ultimately agree on z, what is the percentage represented by (z-x)/x. Got it?It's got to be a function of y, although I would say z asymptotically approaches zero if y increases too much above x.How in the world would z approach zero? Who counter offers with 0? I think you mean z approaches x? That doesn't make any sense either. It's like you're suggesting some sort of laffer curve relationship.No, I'm saying if your counter is too high they are going pull the offer altogether.That would be a different function considering I stipulated that both parties ultimately agree on z.